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Java - Math.sqrt() Examples

Java Java API 

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Class:

java.lang.Math

java.lang.Objectjava.lang.Objectjava.lang.Mathjava.lang.MathLogicBig

Method:

public static double sqrt(double a)

Returns the correctly rounded positive square root of a double value.


Examples


package com.logicbig.example.math;

public class SqrtExample {

    public static void main(String... args) {
        findSqrt(9.0);
        findSqrt(25.0);
        findSqrt(49.0);
        findSqrt(65.0);
        findSqrt(-81.0);
        findSqrt(0.0);
        findSqrt(0.0 / 0.0);
        findSqrt(Double.POSITIVE_INFINITY);
    }

    private static void findSqrt(double a) {
        double result = Math.sqrt(a);
        System.out.printf("Math.sqrt(%s) = %s%n", a, result);
    }
}

Output

Math.sqrt(9.0) = 3.0
Math.sqrt(25.0) = 5.0
Math.sqrt(49.0) = 7.0
Math.sqrt(65.0) = 8.06225774829855
Math.sqrt(-81.0) = NaN
Math.sqrt(0.0) = 0.0
Math.sqrt(NaN) = NaN
Math.sqrt(Infinity) = Infinity

See Also